Question

If you have a heat engine with a hot reservoir of 515°C and a cold reservoir of 190°C, what is the thermal efficiency of the system?

Answer 1

someone help me

Answer 2

by definition the efficiency \( \large \eta \) of your termal machine is:
\[\Large \eta = \frac{{{T_1} - {T_2}}}{{{T_1}}}\]
where \( \large T_1, T_2 \) are the absolute temperatures., namely:
\[\Large \begin{gathered}
{T_1} \cong 515 + 273 = 788 \hfill \\
{T_2} \cong 190 + 273 = 463 \hfill \\
\end{gathered} \]
so after a substitution, we get:
\[\Large \eta = \frac{{{T_1} - {T_2}}}{{{T_1}}} = \frac{{788 - 463}}{{788}} = ...?\]