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find the limit as x approaches infinity of ((4x^3)-x-5)/(4x-7)
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\[\lim_{x \rightarrow \infty}\frac{ 4x ^{3}-x-5 }{ 4x-7 }\]
and your working now?
same as the last question? would I divide everything by the highest power of x?
yep, divide by highest power if x
*of x
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I get 4/0 and you cannot have a 0 in the denominator so as @EllaElla02 said, the limit does not exist.
depends on how your book defines infinity ... it is either DNE or +inf
in class we use DNE
in other courses, the would say +inf :)
because it covers - inf and +inf so its safer
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