Question

Which element is oxidized in the following reaction:
CuO(s) + H2 (g) Cu(s) + H2O (l) kind of tricky

Answer 1

this what I had got so far CuO + H2 -->
Cu + H20 We need to figure out the charges on each of the elements
(+2)(-2)..(0) -->(0)..(+1)(-2) Cu goes from a charge of +2 to 0 H
goes from a charge of 0 to +1 One is gaining electrons and therefore
reduced One is losing electrons therefore oxidized

Answer 2

that the part I need help on

Answer 3

CuO + H2 -->Cu + H20 right

Answer 4

yeah okay thanks