The moon's mass is approximately 1% of the earth's mass. How does the gravitational pull of the earth on the moon compare with the gravitational pull of the moon on the earth?

Question

anonymous · Answer

Let
Mass of Earth be Me
Mass of Moon Mm
Gravitational Pull of Earth Fe
and Gravitational Pull of Moon Fm
$$M_{e},M_{m},F_{e},F_{m}$$
These are the quantities
Now the gravitational pull is proportional to the mass of the body
so
$$F \propto M$$
Removing the proportionality we introduce a constant k
$$F=kM$$
Now for earth and moon we have the equations
$$F_{e}=kM_{e}$$
$$F_{m}=kM_{m}$$
Dividing these we get
$$\frac{F_{e}}{F_{m}}=\frac{M_{e}}{M_{m}}$$
From this we get
$$F_{m}=\frac{M_{m}}{M_{e}}.F_{e}$$
But you are also given Mm as 1% of Me
so
$$M_{m}=\frac{1}{100}.M_{e} \implies M_{e}=100M_{m}$$
Substitute this value in equation for Fm and simplify

melodious · Answer

can explain this to me pls
@Nishant_Garg