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Mathematics 22 Online
OpenStudy (janu16):

Which of the following values "completes the square," or creates a perfect square trinomial, for x2 + 10x + ___?

OpenStudy (janu16):

@SolomonZelman

OpenStudy (solomonzelman):

Ok

OpenStudy (janu16):

so how do you figure out the third number

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle (x+\color{red}{ a})^2=x^2+2\color{red}{ a}x+\color{red}{ a}^2 }\) do you understand this rule?

OpenStudy (janu16):

yaa but is there a name for this stuff

OpenStudy (janu16):

i actually take online class and they haven't teached the rules you are teaching me

OpenStudy (solomonzelman):

Oh, then you are a little bit behind, I guess.

OpenStudy (solomonzelman):

I don't recall its name in particular, but I don't think that matters that much,.

OpenStudy (janu16):

they have teached me y=a(x-h)^2+h and ax^2+bx+c for this lessom

OpenStudy (janu16):

y=a(x-h)^2+k

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle (x+\color{red}{ a})^2= }\) \(\large\color{black}{ \displaystyle (x+\color{red}{ a})(x+\color{red}{ a})= }\) \(\large\color{black}{ \displaystyle x\cdot x+x\cdot\color{red}{ a}+x\cdot \color{red}{ a}+\color{red}{ a}\cdot\color{red}{ a}= }\) \(\large\color{black}{ \displaystyle x^2+x\color{red}{ a}+x \color{red}{ a}+\color{red}{ a}^2= }\) \(\large\color{black}{ \displaystyle x^2+2\color{red}{ a}x+\color{red}{ a}^2 }\) `--------------------------------------------` Is this process I did familiar to you?

OpenStudy (janu16):

yaas

OpenStudy (janu16):

this is what i learned

OpenStudy (solomonzelman):

ok, so thus we know that: \(\large\color{black}{ \displaystyle (x+\color{red}{ a})^2=x^2+2\color{red}{ a}x+\color{red}{ a}^2 }\) Okay?

OpenStudy (janu16):

mhm

OpenStudy (solomonzelman):

and we want to get \(x^2+10x\) peace of the equation, to be a perfect square.

OpenStudy (solomonzelman):

\(\large\color{black}{ \displaystyle x^2+10x+{?} }\)

OpenStudy (solomonzelman):

(you want to get your equation to be like: \(\large\color{black}{ \displaystyle (x+\color{red}{ a})^2=x^2+2\color{red}{ a}x+\color{red}{ a}^2 }\) )

OpenStudy (solomonzelman):

10 is same as 2a, right?

OpenStudy (janu16):

ook

OpenStudy (solomonzelman):

Compere these two: \(\large\color{black}{ \displaystyle x^2+10x+{?} }\) \(\large\color{blue}{ \displaystyle x^2+2ax+a^2 }\)

OpenStudy (solomonzelman):

Compare*

OpenStudy (solomonzelman):

((the question mark is \(a^2\) ))

OpenStudy (solomonzelman):

so if 10 is 2a, then \(a^2\) is going to be equal to what?

OpenStudy (janu16):

soory hold on im lagging

OpenStudy (janu16):

2ax? or a2

OpenStudy (solomonzelman):

Again, 2a in our case is what?

OpenStudy (janu16):

10

OpenStudy (solomonzelman):

so if 2a=10 then a\(^2\)=?

OpenStudy (janu16):

10?

OpenStudy (solomonzelman):

ok, 2a=10 then a=?

OpenStudy (janu16):

im really not sure about thiss

OpenStudy (solomonzelman):

2a=10 divide by 2 on both sides, and you get that a=5

OpenStudy (janu16):

wait oyu divide?

OpenStudy (solomonzelman):

Yes, if 2 times a is 10. Then one a is 5.

OpenStudy (janu16):

ohhok so divide so the last blank would be 5

OpenStudy (solomonzelman):

(( a\(^2\) is same as \(a \times a\). )) So, if a is 5, then \(a \times a\) is \(5\times 5\). That will be equal to \(25\).

OpenStudy (janu16):

5^2? right

OpenStudy (solomonzelman):

yes, and that is same thing as "5×5". And this is going to be equal to 25 as you know.

OpenStudy (solomonzelman):

So, now you have: \(\large\color{black}{ \displaystyle x^2+10x+{\underline{25}} }\) \(\large\color{blue}{ \displaystyle x^2+2ax+a^2 }\)

OpenStudy (janu16):

ohok and what was tht formula you used? I just wanna write it down

OpenStudy (solomonzelman):

\(\LARGE\color{black}{ \displaystyle \color{blue}{x}^2+2\color{red}{a}\color{blue}{x}+\color{red}{a}^2=(\color{blue}{x}+\color{red}{a})^2 }\)

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