A box is to be constructed from a sheet of cardboard that is 10 cm by 50 cm by cutting out squares of length x by x from each corner and bending up the sides. What is the maximum volume this box could have? (Round your answer to two decimal places.)
@ganeshie8
@Hero
@dan815
@pooja195
@triciaal
i already did it but i got it wrong 2 times please help
is this calculus?
yes
did you draw a picture of what is going on ?
u want me to show u what i have gotten so far?
yes i did i got the equation (50-2x)(10-2x)(x)
then all together 4x^3-120x^2+500x
ok, now the derivative wrt x
what do u mean
then i found the maximum of the graph of 4x^3-120x^2+500x
and i got 3.4978761
you have \[ V = 4x^3-120x^2+500x \] and people find the derivative of that \[ \frac{dV}{dt} = 12x^2 -240x + 500 \] and set = to zero \[ 12x^2 -240x + 500=0\\ 3x^2 -60x+125=0 \]
and now do i find the maximum of that?
you find what x's make the equation 0 use the quadratic formula
so now i use the quadratic formula or do i put it in the graphing calculator and find the maximum?
we don't want the maximum of the derivative, we want to find the x value that makes the derivative 0. so we solve for x in 3x^2-60x+125=0 using the quadratic formula
and then my answer from that is the final answer?
i got this
\[60+-\sqrt{-5100} all divided by 6
you should get a real number
i dont know how to simplify sqrt
im really bad at it
the number inside the square root should be -60*-60 - 4*3*125 that is not -5100
i got 2100 sorry
I would use a calculator and get a decimal answer. they say (Round your answer to two decimal places.)
i am using a caluclator
i did 4(3)125 and got 1500 then -60*-60 is 3600 and those 2 subtracted is 2100 right???
yes so \[ x = \frac{60\pm\sqrt{2100}}{6} \]
i got 60+10 sqrt{21} all divided by 6 is that right
@phi
that root will give you 10+ (sqrt(21))/6 which is bigger than 10 one of your sides is length 10, so x has to be smaller than 10 I would use the other root.
i got 2.362373842
yes, that looks ok. round to 2 decimal places.
so 2.36 is the final answer
yes
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