Question

I really need help with this please. :)

Here is a picture of the problem: https://cdn.ple.platoweb.com/EdAssets/2aa74bea51264416af45cb620a392471?ts=635545843843870000

If a = 24 mm, c = 26 mm, and m∠B = 33°, what is the approximate area of ABC?

1. 261.67 mm2

2. 54.46 mm2

3. 169.93 mm2

4. 339.85 mm2

Answer 1

This is a right triangle?

Answer 2

I think so.

Answer 3

Ok, then you can use the Pythagorean theorem to find the side b.

Answer 4

I would do that, but it is a degree instead of a number.

Answer 5

I am saying to use the `. a² + b² = c² . `

Answer 6

24²+b²=26²

Answer 7

Okay. Thank you so much!

Answer 8

we aren'tdone yet, are we?

Answer 9

Did you find the side b?

Answer 10

(It will be a precise, natural number, answer)

Answer 11

I'm working on it.

Answer 12

Ok, sure, take your time:)

Answer 13

I got 10.

Answer 14

Oh, very good. that is right!

Answer 15

So you can already tell which choice is closer to the area.

Answer 16

24 right?

Answer 17

I wonder that they do not have the answer choice for that....

Answer 18

So, the test makers didn't put the correct choice on it?

Answer 19

No, I think it is rather our mistake that we assumed that your triangle is a right triangle.

Answer 20

hmmm

Answer 21

Okay, so how would we solve this now?

Answer 22

I think we need to apply the law of cosines.
\(b^2=a^2+c^2-2ac{\rm Cos}(B)\)

Answer 23

have you covered the law of cosines yet?

Answer 24

Not yet, but this is supposed to be a Algebra 1 study.

Answer 25

https://www.mathsisfun.com/algebra/trig-cosine-law.html

Answer 26

hmmm so.. haemm
I think is safe to assume then, that is a right triangle

Answer 27

This is a good link. mathisfun is always easy to read:)

Answer 28

yes jdoe, I assumed that the first I encountered it, but there is no option of 120.

Answer 29

well, right... I'd use the law of cosines, but if your teacher hasn't covered, there's no sense in giving you this exericse yet

Answer 30

Thank you for the link, I will check it out.

Answer 31

law of cosines and Heron's formula to get the area
then again, you may not have covered heron's formula either

you might think the formula has a two long legs, but it doesn't =)

Answer 32

\(b^2=c^2+a^2-2(a)(c){\rm Cos}(B)\)

\(b^2=26^2+24^2-2(24)(26){\rm Cos}(33)\)

\(b=\sqrt{26^2+24^2-2(24)(26){\rm Cos}(33)}=14.33\)