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Algebra 14 Online
OpenStudy (anonymous):

Help me solve this absolute value equation?

OpenStudy (anonymous):

\[2\left| x+2 \right|-1=5\]

OpenStudy (anonymous):

\[2\left| x+2 \right|=5+1=6\] \[\left| x+2 \right|=\frac{ 6 }{ 2 }=3\] \[x+2=\pm3\] find x

OpenStudy (anonymous):

x=1

OpenStudy (danjs):

yes, remember the abs value can have a + or - value and be true, like the last line above

OpenStudy (anonymous):

what about the equation \[2\left| x+2 \right|-1=-5\]

OpenStudy (anonymous):

I got zero but i know that's not the answer

OpenStudy (danjs):

--solve for the absolute value quantity.\[\left| something \right| = c\] --set that 'something' equal to + or - c \[something = +c~~~~or~~~~something=-c\]

OpenStudy (danjs):

solve both of those for x...

OpenStudy (anonymous):

would it be -1?

OpenStudy (danjs):

you should get 2 answers ,

OpenStudy (anonymous):

My first answer was x=1, I'm trying to solve the second equation now. I'm unsure of the answer because I know I'm taking the wrong steps

OpenStudy (danjs):

that one is a bit different, just looked at it

OpenStudy (anonymous):

Yes, the second equation is negative

OpenStudy (danjs):

The absolute value is greater than or equal to zero, so that one will not have any answers

OpenStudy (anonymous):

my options for that equation is -1 or -5

OpenStudy (danjs):

\[2*\left| x+2 \right|-1=-5\] \[\left| x+2 \right|=-2\] false, no solution

OpenStudy (anonymous):

@surjithayer

OpenStudy (anonymous):

x+2=3,find x x+2=-3,find x

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