solve bx-cx=7 for x
Do you know anything like the folowing rule? \(\large\color{black}{ \displaystyle ab+zb=(a+z)b }\)
Don't be afraid to say no....
I really dont know
it is fine.
Ok, would you agree with me if I said that: \(7x-4x=3x\) ?
no hold on
Here is the full question, with options
I don't really need that to do it..... I am just trying to get you to understand how to work ouy the solution:) So, back to what I asked, if you will. In general: \(7x-4x=3x\) Do you agree with me or not?
I do
Ok, and same way: \(10x-2x=8x\) \(9x-3x=6x\) and so forth.
Now, when you do \(bx-cx\) you are going to have a "b-c" number of x's. Right?
Yes
So, you can re-write this: \(bx-cx=7\) as: \((b-c)\times x =7\)
good with the step that I did just now, or you have questions about it?
Good with the steps
Ok, so we have so far: \((b-c)\times x=7\) ---------------------- If I had \(4x=8\), and I wanted to solve for x, THEN, I would divide both sides by 4. \(4x\div4=8\div 4{~~~~~}\Rightarrow{~~~~~} x=2\)
So, what whould I do when instead of 4 (as I showed in the example), I have a \("b-c"\) (as we have in our problem now).
Alright I sorta got it
Ok, s when we have: \((b-c)\times x=7\) we are going to divide both sides by: \((b-c)\)
Can you preform this division for me please?
perform*
x/(b-c) ?
x=7/(b-c)
Thank You :)
Join our real-time social learning platform and learn together with your friends!