A closed container has 4.02 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container?
6.71 grams, because (4.02 ⋅ 1.67) ⋅ (1023 ⋅ 10–24) = 6.7134
5.69 grams, because (4.02 + 1.67) ⋅ (1023 ⋅ 10–24) = 5.69
0.67 grams, because (4.02 • 1.67) ⋅ (1023 ⋅ 10–24) = 6.7134 • 10–1
0.57 grams, because (4.02 + 1.67) ⋅ (1023 ⋅ 10–24) = 5.69 ⋅ 10–1
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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (michele_laino):
we have to compute this:
\[\Large \left( {4.02 \cdot {{10}^{23}}} \right) \cdot \left( {1.67 \cdot {{10}^{ - 24}}} \right) = ...?\]
OpenStudy (anonymous):
am i adding
OpenStudy (anonymous):
@Michele_Laino
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OpenStudy (anonymous):
Its D
OpenStudy (anonymous):
because you have to 4.02 + 1.67
OpenStudy (anonymous):
@Michele_Laino
OpenStudy (michele_laino):
you have to multiply, here are your steps:
\[\large \left( {4.02 \cdot {{10}^{23}}} \right) \cdot \left( {1.67 \cdot {{10}^{ - 24}}} \right)= \left( {4.02 \cdot 1.67} \right) \cdot {10^{23 - 24}} = ...?\]
OpenStudy (anonymous):
omg
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OpenStudy (anonymous):
do i have to do this
OpenStudy (michele_laino):
yes!
OpenStudy (anonymous):
Its actually C
OpenStudy (anonymous):
you have tp multiply 4.02 * 1.67
OpenStudy (michele_laino):
yes!
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