Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

How do I solve Polynomial equations?

OpenStudy (anonymous):

3.2x^3+4.8x+3.7 2.1x^3+6.3x-2.9 --------------- ?

OpenStudy (amistre64):

the sum of 2 polynomials is a polynomial ... you just add up like parts.

OpenStudy (amistre64):

think of them as a hidden number, and the x parts determine the placement of a digit.

OpenStudy (anonymous):

So the 3.2x^3 over 2.1x^3 part is 3.3x^9?

OpenStudy (amistre64):

assuming that we are adding them to start with ... almost. x^3 is a common factor; like 3a + 2a = (3+2)a, not 5a^2

OpenStudy (amistre64):

3.2x^3 + 2.1x^3 = (3.2 + 2.1)x^3

OpenStudy (anonymous):

but how would i write that on a graph? it's just boxes i place the digits in.

OpenStudy (amistre64):

im not sure what you mean by that

OpenStudy (amistre64):

can you post a picture of your problem?

OpenStudy (anonymous):

OpenStudy (amistre64):

yeah, you are just adding like parts ...

OpenStudy (amistre64):

what is 3.2 + 2.1 ?

OpenStudy (anonymous):

just the first part of the equation. what would the answer look like?

OpenStudy (amistre64):

what is 3.2 + 2.1 ?

OpenStudy (anonymous):

5.3 lol...

OpenStudy (amistre64):

then we can work it as: \[3.2x^3 + 2.1x^3 = (\color{red}{3.2 + 2.1})x^3=\color{red}{5.3}x^3\]

OpenStudy (anonymous):

ok. i think i might have it. just give me a second.

OpenStudy (amistre64):

k

OpenStudy (anonymous):

ok so i hav it this far. look right so far? what symbols would i use? (+/-)

OpenStudy (amistre64):

is 6+4 a positive or negative number?

OpenStudy (anonymous):

positive?

OpenStudy (amistre64):

then that ones a + is 3.7-2.9 a positive or negative number?

OpenStudy (anonymous):

positive? 0.8

OpenStudy (amistre64):

yes, so its a + the operation symbol just indicates the sign of the resulting operation you did on the numbers. a postive result gives us + a negative result gives us -

OpenStudy (anonymous):

Ok. Thank you so much! It seems kinda easy now that I know how it's done. Thanks!

OpenStudy (amistre64):

good luck :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!