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derivate f(x)=ln(x2+3), x0=l f'(x)=
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use the chain rule
does that help?
but i don;t know to do that
you haven't used the chain rule?
no, i want to help my friend
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with your help^^
ln(x^2 + 3) is a compound function - function within a function so we can write it as f(g(x) where g(x) = x^2 + 3 so derivative of f(g(x) = f'(g)x) * g'(x) = 1/ (x^2 + 3) * 2x = 2x/ (x^2 + 3) - that is f'(x)
i used the standard derivatives D (ln u) = 1/u. and D (x^n) = nx^(n-1)
Are you clear with evertthing? What other examples of chain rule, or what? (Please reply, don't just sit silent. We will help you)
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