Question

I have an aluminum cylinder; length =10cm and radius =.25cm
density of aluminum =2.70g/cm3
1Al atom =4.48*10-23g

How many Al Atoms are in the cylinder?
Would you find the volume first? then do mass = d*v? and divide that by the mass of 1 Al atom?

Answer 1

@toxicsugar22 do you know?

Answer 2

@3-sfera doing what i explained in the question i got 1.18*10^23 atoms of Al, do you know if i did this correctly

Answer 3

let me do some math

Answer 4

no my result is 1,2x10^27

Answer 5

i did Vcylinder = pi r^2(h)
pi(.25^2)(10) = 1.96cm^3

then mass = d*v
m= 2.70*1.96 = 5.292

then 5.292 / 4.48*10^-23 = 1.18*10^23

Answer 6

in the question it says taht 1 atom of Al = 4.48 * 10^-23 g

Answer 7

my solution is with the molar mass, your volume is incorrect i think.
the volume is 1,96*10^3 cm^3

Answer 8

so my number of atoms is correct too? 1.18*10^23

Answer 9

uhm actually not :).. maybe just some different approximation..maybe the mass on your book is wromg

Answer 10

Well by the book, the answer is correct then?

Answer 11

@aaronq can you please help?

Answer 12

the answer with your atom mass is 1.8*10^26

Answer 13

sorry for late i'm a little bit busy

Answer 14

i don't understand how you got that.

Answer 15

oh flutter wait.. the radius is 0.25

Answer 16

*flutter

Answer 17

ahha i wanna write f*u*c*k but it shows flutter

Answer 18

by the way, i misread the radius

Answer 19

your answer is correct i think

Answer 20

sorry @Savannah_Lynn13