Quick Help: For the functions f(x) = 2x + 3 and g(x) = 6x + 2, which composition produces the greatest output? Neither composition produces an output. Both compositions produce the same output. f(g(x)) produces the greatest output. g(f(x)) produces the greatest output.
\(\large\color{blue}{ \displaystyle f(x)=2x+3 }\) \(\large\color{red}{ \displaystyle g(x)=6x+2 }\) \(\large\color{blue}{ \displaystyle f(\color{red}{g(x)})=2\left( \color{red}{6x+2}\right)+3 =? }\)\ \(\large\color{red}{ \displaystyle g(\color{blue}{f(x)})=6\left( \color{blue}{2x+3}\right)+2 =? }\)
I coloered each function in its color, and here belower f(x) and g(x), I am showing how to set up the f(g(x)) and g(f(x))....
this migh be confusing, say so if it is.
What do I do next?
evaluate each composition
how do i do that?
expand the parenthesis in: \(\large\color{blue}{ \displaystyle f(\color{red}{g(x)})=2\left( \color{red}{6x+2}\right)+3 }\)
then simplify as much as you can (by adding like terms)
how do I find x?
you don't need to
just simplify the f(g(x)) and g(f(x)) as much as you can
Again, posting them so that you won't need to scrol way back \(\large\color{blue}{ \displaystyle f(\color{red}{g(x)})=2\left( \color{red}{6x+2}\right)+3 =? }\)\ \(\large\color{red}{ \displaystyle g(\color{blue}{f(x)})=6\left( \color{blue}{2x+3}\right)+2 =? }\)
f(g(x))= 19 g(f(x))= 32 right?
So, D. is the correct choice?
f(g(x)) = 2(6x+2)+3 = 12x+4+3 = 12x + 7 -------------------------------------- g(f(x)) = 6(2x+3)+2=12x+18+2=12x+20 did you plug in 1 for x after that?
But you didn't have that x=1 for that, did you? (Not that it matters..... g(f(x)) is shifted 13 units up from f(g(x)), and for any x it is thus g(f(x)) is greater by 13 units.)
no I didn't.
how did you get 19 and 32 then?
I dunno, how did u get the 4 this equation? --> f(g(x)) = 2(6x+2)+3 = 12x+4+3 = 12x + 7
I expanded, because: |dw:1441674897461:dw|
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