Question

I'm trying to check my answer but it appears wrong based on what the book says. Factors by grouping.

24x^3-36x^2+72X-108

my answer was : (2x-3)(12x^2+36)
please help

Answer 1

yours in incomplete. 12x + 36 can be factored further by pulling a gcf out

Answer 2

but I did?
here is my problem:

Answer 3

24X^3-36x^2+72X-108

12x2(2X-3)+36(2x-3)
(2x-3)(12x2+36)

???? NOt sure what I did wrong Thanks in advance.

Answer 4

you didn't do anything wrong, it's just that there's another step.
You have (2x - 3)(12x² + 36)
2x - 3 can't be factored anymore
12x² + 36 can have a gcf of 12 factored out

Answer 5

(2x-3)12(x^2+3)

Answer 6

\[12(2x-3)(x^2+3)\]

Answer 7

@peachpi thats right:)

Answer 8

So I need to factor my answer which I already had factor previously!

So it's possible that once you have factor a problem your answer my still need to be factor a bit more. ?

Answer 9

yes, that's fairly often the case

Answer 10

yes.unless you get it in the most simplest form

Answer 11

remember in these cases you got to reduce the equation to the simplest form

Answer 12

would there had been another way to factor from the start or this would of been the only way which and I would just had to do the extra step at the end ?

Answer 13

this is the best possible easy way

Answer 14

but my final answer would not match meaning I have a negative and a positive answer. For some reason I though that would be wrong ?

Answer 15

whats the answer given in your book

Answer 16

The book says the opposite?
= 12(2x-3)(x2+3)

Answer 17

thats what you have got

Answer 18

this was my original answer:

(2x-3)(12x2+36)

Answer 19

great I just figured it out thanks

Answer 20

would you please take a look at another problem for me?

Answer 21

say

Answer 22

a^3-3a^2-2a+6

my answer was way off even after changing the - to + and making the - 2a to +(-2a+6)?

Answer 23

answer will be (a^2-2)(a-3)

Answer 24

is it okay

Answer 25

that is the answer but can you explain how?

Answer 26

or show

Answer 27

yes

Answer 28

a^3-3a^2-2a+6
a^3-2a-3a^2+6
a(a^2-2)-3(a^2-2)
(a-3)(a^2-2)

Answer 29

did you now understand?

Answer 30

doing the problem myself following your steps....

Answer 31

go on buddy............:)

Answer 32

sorry but I don't understand why you re- arrange the order when doing factoring by grouping>?

Answer 33

I got the same answer but did not re-arrange the problem

Answer 34

rearangement makes it more clear and simple