Question

HELP! (picture below)

Answer 1

Solve for \(C\): \[133 = \dfrac{9}{5} C + 32\]

What I did, I used the given Fahrenheit temperature of 133, and substituted its value for the variable \(F\).

Answer 2

ok makes sense

Answer 3

If you want I can check your answer if you would like, once you solve for C.

Answer 4

how do i solve for c though...

Answer 5

Isolate the like terms to one side of the equation.

Answer 6

alright

Answer 7

\[133 = \dfrac{9}{5} C + 32\]
\[133 - 32 = \dfrac{9}{5} C\]
\[\cdots\]

See where I am going, by isolating the like terms?

Answer 8

how do i subtract 9/5 from 133?

Answer 9

They are not like terms, so you cannot.

Here is an example:
\[44 = 3C + 4\]
\[\Rightarrow 44 - 4 = 3C\]
\[\Rightarrow 40 = 3C\]
\[\Rightarrow \dfrac{40}{3} = \dfrac{3C}{3}\]
\[\Rightarrow 13.3333... = C\]

Answer 10

so do i subtract 32?

Answer 11

Yes, so \(133 - 32 = 101\).
\[\Rightarrow 101 = \dfrac{9}{5} C\]
\[\Rightarrow \dfrac{101}{1.8} = \dfrac{1.8C}{1.8}\]

To understand where I got \(1.8\), I converted the fraction to a decimal. \(\dfrac{9}{5} = 1.8\)

All you have to do is simplify now.

Answer 12

i got 56.1111....

Answer 13

Correct. \[C \approx 56.111\]

Answer 14

Remember your question also asks to round to the nearest tenth.