Question

help! (picture in comments)

Answer 1

Ok let's see what we know so far...\[\large\rm \color{green}{P}=2\color{royalblue}{L}+2\color{orangered}{W}\]
They told us that the \(\large\rm \color{green}{\text{perimeter is 212}}\).
So let's plug that in.\[\large\rm \color{green}{212}=2\color{royalblue}{L}+2\color{orangered}{W}\]

Answer 2

They told us that the \(\large\rm \color{royalblue}{\text{Length is two more than the Width}}\).
We can write that relationship like this: \(\large\rm \color{royalblue}{L=W+2}\)

Answer 3

yes

Answer 4

\[\large\rm \color{green}{212}=2\color{royalblue}{(L)}+2\color{orangered}{W}\]We plug this information into our equation, replacing L.

Answer 5

right

Answer 6

\[\large\rm \color{green}{212}=2\color{royalblue}{(W+2)}+2\color{orangered}{W}\]

Answer 7

And from there, you have an equation involving only ONE VARIABLE! :)
So you can proceed to solve for W.

Answer 8

What do you think? :O

Answer 9

lemme work it out

Answer 10

212=4w+4?

Answer 11

So you ditributed and then combined like-terms?
Ya that's a good start! :)

Answer 12

52=w?

Answer 13

Looks good!
And then don't forget about the fact that the \(\large\rm \color{royalblue}{\text{Length is two more than the Width}}\).

Answer 14

so 54?

Answer 15

yay good job \c:/

Answer 16

thanks!