Subtract a first degree binomial from a second degree trinomial.

Question

sweetburger · Answer

ax^2 +bx +c -(bx +c) maybe this?

anonymous · Answer

$$ax^2 + bx + c - (bx + c)$$ would be your answer I believe.

sweetburger · Answer

looks good

anonymous · Answer

Let
$$p_{1}(x)=ax^2+bx+c$$
$$p_{2}(x)=dx+e$$
$$p_{1}(x)-p_{2}(x)=\Delta p(x)=ax^2+bx+c-(dx+e)=ax^2+(b-d)x+(c-e)$$
Special Case:
When
$$d=b, e=c$$
$$\Delta p(x)=ax^2+(b-b)x+(c-c)=ax^2+0x+0=ax^2$$

capital Greek letter delta is frequently used to denote a change in 2 quantities
I've p(x) as a way to denote polynomials
It's another way of writing things, you'll learn along

anonymous · Answer

Could you give me a medal please? For best effort?

sweetburger · Answer

@160UTurn you just rewrote what i said to be brutally honest