Question

x^2+4x-5/1-x

Answer 1

Did you try to factor the numerator?

Answer 2

I"m not sure how to, please show me how

Answer 3

Factoring is kinda hard for me to figure out

Answer 4

ok. start by finding 2 numbers that multiply to -5 and add up 4.
What are the factors of 5?

Answer 5

What numbers multiply to give 5?

Answer 6

5 and 1?

Answer 7

alright 5 and 1 multiply to 5.
We have -5 in this problem, so either 1 or 5 has to be negative. Which one has to be negative for them to add up to 4?

Answer 8

1?

Answer 9

right, so the two numbers that multiply to -5 and add to 4 are \(5\) and \(-1\).
So we can factor the numerator as \((x + 5)(x-1)\)

Answer 10

The denominator can get a -1 factored out and we written as \(-(x-1)\)

Answer 11

So then you have
\[\frac{ (x+5)(x-1) }{ -(x-1) }\]
and you can cancel

Answer 12

-(x+5)?

Answer 13

yes

Answer 14

Alright back

Answer 15

So whats the next step?

Answer 16

\(-(x-5)\) is the answer

Answer 17

I only have these options?

Answer 18

we got -(x+5) after canceling. distribute the negative to get -x-5

Answer 19

thanks