Question

im suppose to expand using the partial fractions.

Answer 1

\[\frac{ -5x+4 }{ x^2-16 }\]

Answer 2

@raiders88

Answer 3

Did you factor the denominator?

Answer 4

yep x-4 and x-4

Answer 5

It's actually (x + 4)(x - 4), from a difference of squares
Then you can write this
\[\frac{ -5x+4 }{ (x+4)(x-4) }=\frac{ A }{ x+4 }+\frac{ B }{ x-4 }\]
Then you have to multiply the whole equation by the denominator on the left side

Answer 6

uhh nope it says that there both -'s so idk and the only part i got right n u is the plus in between and the 4's

Answer 7

ok, that might have been a mistake in the program. do you want solve it this way since it didn't work that way before.

Answer 8

uhh hold up imma look at the video soo il message u when i have a definite answer kk

Answer 9

hey uhh try this site https://www.khanacademy.org/math/algebra2/polynomial_and_rational/partial-fraction-expansion/v/partial-fraction-expansion-1

Answer 10

no offense, I don't need to try khan academy I know how to do this. Your issue is that you factored the denominator wrong.

http://www.wolframalpha.com/input/?i=factor+x%5E2-16

Answer 11

ohhh ok ill try this site 2

Answer 12

np and foil these out and you'll see
\((x-4)(x-4)=x^2-8x+16\)
\((x-4)(x+4)=x^2-16\)

Answer 13

ok