more implicit differentials for what values of x does the curve y^2 -x^4 + 2xy -18x^2 = 10 have vertical tangent lines?
@ganeshie8 @IrishBoy123 any ideas?
Horizontal tangent lines when: \(\large\rm y'=0\) Vertical tangent lines when: \(\large\rm y'=\frac{stuff}{0}\) Have you tried finding your y' yet? :)
yes
i feel i messed up somewhere though so im redoing that right now
im getting \[y'= \frac{ 4x(x^2+9) }{ 2(y+x) }\]
Hmm I think there is another term on top. Did you forget to product rule again? :)\[\large\rm y^2 -x^4 + \color{orangered}{2xy} -18x^2 = 10\]
no i just simplified from 4x^3 + 36x
But where is the -2y in the numerator? :o hmm
oh your totally right
argh your so clever :P
\[\large\rm y^2 -x^4 + 2xy -18x^2 = 10\]Differentiating gives,\[\large\rm 2yy'-4x^3+2y+2xy'-36x=0\]That's your first step ya? :D
you're* that's gonna bug me, i had to lol
yeah i even crossed it out and all i guess it just slipped my mind when i was rewriting it on the other side of the equal sign
anyway so its \[y'= \frac{ 4x^3 + 36x + 2y }{ 2(x+y) }\]
Woops, -2y on top I think ya?
Anyway, let's just get rid of all the 2's I guess,\[\large\rm y'=\frac{2x^3+18x-y}{x+y}\]That's the only simplification that really cleans it up nicely.
:( yes , okay so now what?
This derivative function is undefined when the denominator is zero. (This is also when we're getting vertical tangents.)
So vertical tangent when the denominator is zero, \(\large\rm x+y=0\)
Overheat again? :) LOL
|dw:1441787497363:dw| where its undefined? :P
yep :( i need a new computer
Hmm ya that's a weird answer :o I do something wrong?
anyway one of the answer choices is x = -y so i think that's the answer right?
yay team \c:/ it just doesn't make a whole lot of sense with the graph of the function :D I guess I just need to think about it a sec lol
I think that's about right, it's either \(\sf y=-x\) or \(\sf x=-y\).
thank you once more :D
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