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Mathematics 7 Online
OpenStudy (matlee):

is surjective even or odd?

OpenStudy (zzr0ck3r):

?

OpenStudy (matlee):

Hi

OpenStudy (zzr0ck3r):

hi

OpenStudy (matlee):

do you know what surjective is?

OpenStudy (zzr0ck3r):

yes

OpenStudy (matlee):

how can i tell if its even or odd?

OpenStudy (zzr0ck3r):

A surjective function can be even or odd or neither example even \(f:\mathbb{R}\rightarrow [0,\infty), f(x) = x^2\) is surjective and even odd \(f:\mathbb{R}\rightarrow \mathbb{R}, f(x) = x\) is surjective odd Neither \(f:\mathbb{R}\rightarrow \mathbb{R}, f(x) = 2x+3\) is neither even nor odd but is surjective

OpenStudy (matlee):

my equation is f(x)= x^3 + 0.04x2 +3

OpenStudy (zzr0ck3r):

A function is even if \(f(-x) = f(x) \) for all \(x\) A function is odd if \(f(-x) = -f(x)\) for all \(x\). A function is surjective if for all \(y\) there exists \(x\) such that \(f(x) = y\).

OpenStudy (matlee):

my domain and range are all R

OpenStudy (zzr0ck3r):

that is neither even nor odd. If it were even then \(f(2) = f(-2)\) and it does not. If it were odd, then it would be true that \(f(2) =-f(2)\) and that is not true. Check em to make sure:) It is however surjective

OpenStudy (matlee):

Wow thank you, so i would just put niether

OpenStudy (zzr0ck3r):

even functions are symetrical across the y axis odd functions are symetrical about the origin

OpenStudy (matlee):

what do you mean origin? i recently just joined this precalc class and am already having trouble lol

OpenStudy (matlee):

so the odd ones would look similiar to itself?

OpenStudy (zzr0ck3r):

it means that if you flip it about the x axis and then flip it about the y axis, it looks exactly the same as when you started

OpenStudy (zzr0ck3r):

http://www.mathwords.com/s/symmetric_origin.htm

OpenStudy (matlee):

oo i see

OpenStudy (matlee):

hahah thank you i appreciate your help i can finally move onto question number 3 lol

OpenStudy (zzr0ck3r):

np keep at it

OpenStudy (matlee):

Sure thing goodmirning or goodnight bye

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