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OpenStudy (loganh):
Cow
OpenStudy (anonymous):
Wrong, try again
OpenStudy (loganh):
longhorn?
OpenStudy (anonymous):
x3 what r de babies called.
OpenStudy (loganh):
calf
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OpenStudy (anonymous):
Yay x3
OpenStudy (loganh):
lol
OpenStudy (loganh):
plural calves?
OpenStudy (anonymous):
I do this out of randomness
OpenStudy (loganh):
QUICK! what is 13-5*2?
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OpenStudy (anonymous):
Pemdas!
OpenStudy (loganh):
YAY!
OpenStudy (loganh):
:D
OpenStudy (anonymous):
x3 do I win?
OpenStudy (loganh):
what is the square root of calf
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OpenStudy (loganh):
idku
OpenStudy (idku):
Suppose that there is such a vector X, that:
\(\Large \vec{X}=\vec{\rm Cow}+\vec{\rm Bull}\)
And suppose that \(\Large \vec{\rm Cow}\) and \(\Large \vec{\rm Bull}\) are two vertical and horizontal velocity components respectively.
OpenStudy (anonymous):
meat
OpenStudy (loganh):
Dear god
OpenStudy (loganh):
idku XD
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OpenStudy (loganh):
I have to undo my best response XD
OpenStudy (anonymous):
lol
OpenStudy (idku):
So, you can conclude that:
\(\Large \vec{\rm Cow}=\vec{X}\cos(\theta)\)
\(\Large \vec{\rm Bull}=\vec{X}\sin(\theta)\)
OpenStudy (anonymous):
Lol sin
OpenStudy (idku):
So,
\(\Large \vec{\rm X}=\vec{X}\cos(\theta)+\vec{X}\sin(\theta)\)
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OpenStudy (loganh):
Hmm, enlightenment
OpenStudy (idku):
So if I wanted to find the angle:
\(\Large \vec{\rm X}=\vec{X}\cos(\theta)+\vec{X}\sin(\theta)\)
\(\Large 1=\cos(\theta)+\sin(\theta)\)
\(\Large 1=\cos(\theta)+\sqrt{1-\cos^2(\theta)}\)
\(\Large 1-\cos(\theta)=\sqrt{1-\cos^2(\theta)}\)
\(\Large 1-2\cos(\theta)+\cos^2(\theta)=1-\cos^2(\theta)\)
then,
\(\Large 2\cos^2(\theta)=2\cos(\theta)\)
OpenStudy (loganh):
But what if \[\sin (\theta) \int\limits_{bull}^{cow}\xi \Theta _{1}^{cow*bull}\]
OpenStudy (loganh):
changes completely
OpenStudy (idku):
So either \(\cos\theta=0\) or \(\cos(\theta )\)
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OpenStudy (idku):
i meant cos theta is 1 for the second option
OpenStudy (loganh):
But look
OpenStudy (idku):
hey, why do you have a a reimann zeta function in it:)
OpenStudy (idku):
|dw:1441818273057:dw|defined for x greater than 1 only