An electron in a cathode-ray-tube (CRT) accelerates uniformly from 5.00 ✕ 104 m/s to 6.00 ✕ 106 m/s over 3.00 cm.
(a) In what time interval does the electron travel this 3.00 cm?
(b) What is its acceleration?

Question

An electron in a cathode-ray-tube (CRT) accelerates uniformly from 5.00 ✕ 104 m/s to 6.00 ✕ 106 m/s over 3.00 cm.
(a) In what time interval does the electron travel this 3.00 cm?
(b) What is its acceleration?

irishboy123 · Answer

i would do these in reverse

using the equation of motion $v^2 = u^2 + 2ax$ will give you the acceleration, a, with least fuss 

using the equation of motion $v = u + at$ will give you the time, t

the 3 basic equations l are

1.     $$v = u + at$$ 
2.$$x = ut + \frac{1}{2}at^2$$
3.$$v^2 = u^2 + 2ax$$