Question

Find the domain of the function.
g(x)=^4sq.rt x^2+2x

Answer 1

yep that's what it's supposed to be

Answer 2

scan or link the question pls

Answer 3

sorry, been here done that!

just scan or link it :p

Answer 4

the one you typed is the correct one

Answer 5

scan or link your question

no point is answering to ghosts

Answer 6

i don't know how to scan it and the link wont work since it's under my account name.. you already know what the problem looks like, you sent it yourself, so it should be good enough?

Answer 7

\[\sqrt[4]{x^2+2x}\]

Answer 8

?

Answer 9

what happens if you have this\[\sqrt[4]{-1}\]?
does this exist over the real numbers?

Answer 10

I don't think so since you shouldnt have -'s under a radical

Answer 11

great so you want x^2+2x to be positive or zero right?

Answer 12

yeah

Answer 13

for a number to be positive or equal it must be greater than or equal to 0

Answer 14

so you basically need to solve x^2+2x>=0

Answer 15

to find the domain

Answer 16

do we just get rid of the radical then?

Answer 17

you told me just a sec ago that we didn't want the thing under the radical to be negative
which means we want it to be zero or positive

Answer 18

the thing under the radical was x^2+2x

Answer 19

so you want x^2+2x>=0

Answer 20

it has to be in interval notation

Answer 21

so would I start with (0,_)

Answer 22

you would solve x^2+2x>=0

Answer 23

then we can put an interval notation

Answer 24

x^2>or= -2x

Answer 25

and then would we square both sides?? because then there'd be a negative on the right

Answer 26

\[x^2+2x \ge 0 \\ x(x+2) \ge 0\]
draw a number line
x(x+2) is zero when x=0 or x+2=0

test the intervals