Question

the directions to this problem say: "differentiate"
u=(arcsinx)^2
i dont understand what the "u" means? Do i just take the derivative as normal by using the chain rule by witting u' ??

Answer 1

I think they want you to derive with respect to x. So think of the `u` as like `y`

ie you have

y = (arcsin(x))^2

Answer 2

Yes, you have to find u'
:)

Answer 3

ok thank guys!

Answer 4

oh ya and for this problem, how do i use the chain rule?
f(x)=ln(arctanx)?

Answer 5

alright thanks!

Answer 6

\[\large\rm f(x)=\ln(\arctan x)\]\[\large\rm f'(x)=\frac{1}{\arctan x}(\arctan x)'\]Yes, chain rule :D
Sorry, had to correct my mistake from before lol