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Mathematics 18 Online
OpenStudy (anonymous):

Use the factor Theorem to factor the polynomial completely.

OpenStudy (anonymous):

Given that 2 is a solution; 2x^3+x^2-13x+6=0

OpenStudy (anonymous):

How would I go about solving this?

Nnesha (nnesha):

i guess it's p over q method \[\huge\rm \frac{ p }{ q }= \frac{ constant }{ leading ~coefficient }\] find factors of leading coefficient and factors of constant term

Nnesha (nnesha):

like leading coefficient is 2 and factors 2 and 1 you will write it as \[\frac{ constant }{ leading ~coefficinet }=\frac{ ? }{ \pm 2, \pm 1 }\]

Nnesha (nnesha):

gtg sorry :(

OpenStudy (anonymous):

I'm still confused. The example problem uses synthetic division in the beginning...

OpenStudy (anonymous):

OpenStudy (triciaal):

given that 2 is a solution then (x-2) is a factor. (x-2) is a factor means when you divide the polynomial by the factor there is no remainder. Divide by (x-2) then factor the quadratic

OpenStudy (triciaal):

you already have the polynomial factored what do you need help with?

OpenStudy (anonymous):

The screenshot is an example problem, I was just confused as to what the question was asking.

OpenStudy (triciaal):

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