Use the factor Theorem to factor the polynomial completely.
Given that 2 is a solution; 2x^3+x^2-13x+6=0
How would I go about solving this?
i guess it's p over q method \[\huge\rm \frac{ p }{ q }= \frac{ constant }{ leading ~coefficient }\] find factors of leading coefficient and factors of constant term
like leading coefficient is 2 and factors 2 and 1 you will write it as \[\frac{ constant }{ leading ~coefficinet }=\frac{ ? }{ \pm 2, \pm 1 }\]
gtg sorry :(
I'm still confused. The example problem uses synthetic division in the beginning...
given that 2 is a solution then (x-2) is a factor. (x-2) is a factor means when you divide the polynomial by the factor there is no remainder. Divide by (x-2) then factor the quadratic
you already have the polynomial factored what do you need help with?
The screenshot is an example problem, I was just confused as to what the question was asking.
|dw:1441855710559:dw|
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