Assume that the lottery pays $10 on one play out of 100, it pays $2000 on one play out of 7,500, and it pays $12500 on one play out of 150,000. What probability should be assigned to a ticket's not winning anything?

Question

pulsified333 · Answer

@iLoatheMath do you know how to do this?

anonymous · Answer

I would assume you divide them to find the probability? Hmm..

pulsified333 · Answer

divide what?

anonymous · Answer

I am probably doing this all wrong...is there multiple choice?

pulsified333 · Answer

no

anonymous · Answer

Probability = the number of outcomes that are possible for the terms provided divided by the total number of outcomes possible.

anonymous · Answer

Have you watched khan academy videos possibly? Those usually help me.

pulsified333 · Answer

no I havent

anonymous · Answer

I haven't got the slightest clue how to solve this..I would assume you divide each individual one by how much $ lottery gets. This is statistics isn't it? I took Calculus!);

pulsified333 · Answer

its finite

anonymous · Answer

Oh

kropot72 · Answer

The probability of winning a prize is given by:
$$\large \frac{1}{100}+\frac{1}{7500}+\frac{1}{150000}=\frac{1521}{150000}$$
Therefore the probability of a ticket's not winning anything is:
$$\large 1-\frac{1521}{150000}=\frac{148479}{150000}$$