Let R , the real line be endowned with the discrete topology. Which of the following subsets of R is dense in R
Q Ritself Qc All singletons
Wow, this is some advanced stuff. Just wondering, what branch of mathematics is this?
topology
Nice, wish there was topology class in high school, did you learn about the banach-tarski paradox?
no
Well, it's pretty interesting. I don't think anyone in openstudy knows anything about topology though.
someone does
At least not at 3 AM in the morning lol
yes
So... how hard is topology?
in a way very
All sets are open in the discrete topology. Consider any any set \(U\ne X\). Then \(U^C\) is an open set disjoint from \(U\). This shows that the only dense set is the whole space.
\(U\) is dense means that for any \(x\) in the space \(X=\mathbb{R} _D\), either \(x\) is in \(U\) or \(x\) is a limit point of \(U\). So we take an element \(x\) that is not in \(U\) and see if it is a limit point of \(U\). If \(x\) is a limit point of \(U\) then every open neighborhood around \(x\) intersects \(U\). But since every set is open, due to the topology, we have that \(U^C\) itself is open and contains \(x\) (remember \(x\notin U\)) and of course \(U\cap U^C=\emptyset\). So \(U\) contains all of its limit points. Since \(U\) was not all of \(\mathbb{R}_D\) we have that the only dense set is the entire space.
Clearly the entire space is dense because it contains all of its own points!
@steve816 it really is not, and it is a fun new (new to me...)way of looking at things :)
so, which option is correct
is it R?
It should be very clear. Read it and tell me if you don't understand.
I want you to at least be sure yourself. I did not write all of that out so that you could ask which option it is, click a button, and move on.
ok, from what you said, i its R
@zzr0ck3r
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