Any help would be great:
Function Notation
If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2 · ƒ(4).

Question

Any help would be great:
Function Notation
If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2 · ƒ(4).

misty1212 · Answer

HI!!

anonymous · Answer

Hi

misty1212 · Answer

are you looking for
$$2\times f(4)$$?

anonymous · Answer

Those values are subbed into the expression

anonymous · Answer

*equation

misty1212 · Answer

there is not $g$ in this
your main job is to find 
$$f(4)=4^2+1$$

misty1212 · Answer

then multiply the result by 2

misty1212 · Answer

you got that?

misty1212 · Answer

$$f(x)=^2+1\
f(4)=4^2+1=17\
2f(4)=2\times 17$$

anonymous · Answer

So 34. Why would you not add g of x?

misty1212 · Answer

you asked for $$2f(4)$$right?

misty1212 · Answer

got no $g$ in it

anonymous · Answer

That is where I reached my snag there was no x value so I assumed you simplified.

misty1212 · Answer

lol there is no such thing as "simplify"

misty1212 · Answer

add, subtract, multiply, divide, combine like terms, reduce to lowest terms, write in simplest radical form etc. but not "simplify"

anonymous · Answer

Great so I just have to solve for F(X)?

anonymous · Answer

My original question was just what was on my paper.

anonymous · Answer

So another example. If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find [ƒ(4)] 2. Would just be 257?

anonymous · Answer

x^2 and [f(4)] ^ 2

beginnersmind · Answer

well f(4) is 17. So [f(4)]^2 is 17^2.

beginnersmind · Answer

Or did you change the definition of f(x) to f(x) = x^2?

Then [f(4)]^2 = (4^2)^2 = 16^2 = 256