Question

Just checking.
If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find 2ƒ(1) + 3g(4).

Answer 1

I came up with 42. Is that correct?

Answer 2

That's not what I got.

What did you get for 2f(1) and 3g(4)?

Answer 3

5 and 37

Answer 4

Hm. 2f(1) is 2*(f(1)) or 2 times the value of the function f(x) at 1.

Answer 5

So you should start by calculating f(1) and g(4), by plugging x=1 into f(x) and x=4 into g(x).

Is that what you did?

Answer 6

Yes.

Answer 7

What was your final answer? Maybe I can plug it in and see if it is a match.

Answer 8

The final answer is 43.

f(1) = 2
2f(1) =4
g(4) = 13
3g(4) = 39

Answer 9

I'm guessing x2 meant x^2 in your problem, not 2x.

Answer 10

right. did you do 13*3

Answer 11

Yes.

Answer 12

I think I got it thanks.

Answer 13

No problem. If you need to go through a few more I'll be happy to help.

Answer 14

Alright. If ƒ(x ) = x^2 + 1 and g(x ) = 3x + 1, find [ƒ(2) - g(1)]^2.

Answer 15

Alright, start by calculating f(2) and g(1)

Answer 16

5 and 4