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OpenStudy (albert0898):
if x^2-y^2=12 and x-y=4 what is the value of x^2+2xy+y^2
a. 3
b. 8
c. 9
d. 12
e. 16
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myininaya (myininaya):
you could factor x^2-y^2
and then use what x-y is equal to to find x+y
myininaya (myininaya):
then recall x^2+2xy+y^2 can be written as (x+y)^2
OpenStudy (albert0898):
Erm....
Well here's what I did so far...
I did (x-y)^2 and got x^2 - 2xy + y^2 = 16
I don't know what else to do
myininaya (myininaya):
well can you try what I said?
myininaya (myininaya):
x^2-y^2 can be factored
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myininaya (myininaya):
it is a difference of squares
myininaya (myininaya):
you are given the value of x-y
this will allow you to find x+y
myininaya (myininaya):
and then all you have to do after finding x+y is find (x+y)^2
myininaya (myininaya):
So have you factored x^2-y^2 yet?
OpenStudy (albert0898):
(x-y)(x+y)
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myininaya (myininaya):
\[x^2-y^2=12 \\ (x-y)(x+y)=12 \\ \text{ you are given } x-y=4 \\ \text{ just plug in } \\ 4(x+y)=12\]
\[\text{ and you want to find } (x+y)^2\]
OpenStudy (albert0898):
Ahh!! Now I understand it. Thank you!
myininaya (myininaya):
k great
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