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Mathematics 8 Online
OpenStudy (wintersuntime):

Can someone be nice enough to help me please ?

OpenStudy (anonymous):

Whats the question?

OpenStudy (wintersuntime):

I need help with function A and B

OpenStudy (wintersuntime):

@peachpi

OpenStudy (anonymous):

look at the y's to figure out the pattern. What are they doing to get to the next number? Think in terms of addition and multiplication

OpenStudy (wintersuntime):

multiplying by 2

OpenStudy (anonymous):

right, so that's the answer to #1

OpenStudy (wintersuntime):

For number 2 what it be f(x) = f(n-1) x 2

OpenStudy (anonymous):

For the recursive formula, the first thing is to write the first term. It looks like they're using function notations, so start with f(1). y is 5 when x is 1, so the first part is \[f(1)=5\] Then since it's multiplying by 2, \[f(n)=2f(n-1)\]

OpenStudy (anonymous):

make sense?

OpenStudy (wintersuntime):

So it would only be f(n)= 2f(n-1)

OpenStudy (anonymous):

no, you need to keep f(1) = 5 as well. The recursive formula only gives you a term if you know the previous term

OpenStudy (wintersuntime):

so f(1)=5 2f(n-1)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

actually, no

OpenStudy (wintersuntime):

between 5 and 2 i don't put nothing ?

OpenStudy (anonymous):

Write it like this \[f(1)=5, f(n)=2f(n-1)\]

OpenStudy (wintersuntime):

oh it was like that

OpenStudy (anonymous):

It's saying that the first term is 5. Then to find the second term, multiply the first one by 2. Then to find the third term, multiply the second by 2. and so on. So with a recursive formula, if you want to know the 67th term, you have to know the 66th. But to know the 66th, you have to know the 65th and so on. It's only useful to point out the pattern. Not really useful for anything else

OpenStudy (anonymous):

The explicit one is the useful one. \[f(n)=ar^{n-1}\] a = first term r = number you multiply by (called the common ratio) Plug in your numbers to that formula to get the explicit formula

OpenStudy (wintersuntime):

so i plug in 65?

OpenStudy (anonymous):

no, your first term is 5, and you're multiplying by 2. So plug in 5 for a and 2 for r to get the formula

OpenStudy (anonymous):

\[f(n)=5(2)^{n-1}\]

OpenStudy (wintersuntime):

oh

OpenStudy (anonymous):

the function for A is geometric because it's multiplying by the same number to get to the next term.

OpenStudy (wintersuntime):

Isn't it geometric

OpenStudy (anonymous):

yeah geometric

OpenStudy (anonymous):

I gtg. sorry I can't stay to help on the next one

OpenStudy (wintersuntime):

its okay

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