Ask
your own question, for FREE!
Mathematics
7 Online
OpenStudy (anonymous):
I made an equation and I know the equation will work for it but I need to find out what x equals.
500=[2pi(x/2)]2+x
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (unklerhaukus):
\[500=\big[2\pi(x/2)\big]^2+x\]
OpenStudy (anonymous):
Oops my bad hold on i'll write it correctly.
OpenStudy (anonymous):
\[500=[2\pi(x/2)]2+x\]
OpenStudy (anonymous):
so it's times 2 not to the power of 2
OpenStudy (unklerhaukus):
oh
\[500=\big[2\pi(x/2)\big]\times2+x\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
not sure what to do after I divide both sides by 2
OpenStudy (anonymous):
Yup
OpenStudy (unklerhaukus):
lets look at this bit first
\[[2π(x/2)]× 2\], can you simplify this
OpenStudy (anonymous):
not sure what I did was I divided both sides by 2 to get rid of the 2 but I don't think that was right
OpenStudy (anonymous):
\[4\pi(x/2)\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (unklerhaukus):
Yes, \[[2π(x/2)]×2=4\pi (x/2)\]
now, simplify again
\[=\]
OpenStudy (unklerhaukus):
(combine the 4 and the /2 )
OpenStudy (anonymous):
\[2pix\]
OpenStudy (unklerhaukus):
yeah so you have
\[500=\big[2\pi(x/2)\big]\times2+x\\
500= 2\pi x+x\]
OpenStudy (unklerhaukus):
now can you see a common factor in the right hand side ?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Oh ok that makes sense I got ti from here thanks a bunch!
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!