Question

What is the missing exponent?
(12^-5)^2 l_____l
----------=12
12^-4

Answer 1

@KJSaif

Answer 2

help

Answer 3

you need to know 2 exponent rules \[\huge\rm (x^m)^n=x^{m \times n}\]
and the 2nd one \[\huge\rm \frac{ x^m }{ x^n }=x^{m-n}\]when we divide same bases we should subtract their exponents

Answer 4

so \[\huge\rm (12^{-5})^2 = ?\]

Answer 5

61917364224

Answer 6

use the exponent rule i gave you
don't use calculator .

Answer 7

so \[\huge\rm (12^{-5})^2 = ?\] \[\huge\rm (x^m)^n=x^{m \times n}\]multiply the exponents

Answer 8

20^?

Answer 9

i mean 12^?

Answer 10

what are the exponents \[\huge\rm (12^{-5})^2 = ?\]
?

Answer 11

example \[\huge\rm (2^3)^4=2^{3 \times 4}=2^{12}\]

Answer 12

so 12 ^2

Answer 13

let's solve the numerator first , look at the example i gave you \[\huge\rm (12^{-5})^2 = ?\]

Answer 14

multiply the 2 with the exponent of -12

Answer 15

24

Answer 16

144

Answer 17

\[\huge\rm (12^{-5})^2 = 12^{-5 \times 2}= 12^{??}\]