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Mathematics 14 Online
OpenStudy (anonymous):

Can someone help me with this cube roots question?

OpenStudy (bloomlocke367):

I can try :)

OpenStudy (anonymous):

OpenStudy (anonymous):

I know you have to substitute in the values, but I can't figure out how to simplify to get a whole number. We haven't done imaginaries yet so I know I can't use those.

OpenStudy (bloomlocke367):

What do you mean you can't figure out how to simplify to get a whole number?

OpenStudy (bloomlocke367):

You know what a cubed number is, right?

OpenStudy (anonymous):

All the values in the example questions are getting whole numbers for y. I don't know how when they aren't perfect cubes.

OpenStudy (anonymous):

Yes

OpenStudy (bloomlocke367):

They are perfect cubes >.<

OpenStudy (anonymous):

I'm not sure what to do then

OpenStudy (bloomlocke367):

And take a look at that first one you did. You made a small mistake.

OpenStudy (bloomlocke367):

How did you get 1?

OpenStudy (anonymous):

Oh wait is it -1?

OpenStudy (bloomlocke367):

\[\sqrt[3]{-1}=-1\] and then you also have to subtract 2 from that. \(-1-2=?\)

OpenStudy (anonymous):

Oops, -3.

OpenStudy (anonymous):

Then how do I find the cube root of -3?

OpenStudy (bloomlocke367):

you don't need to find the cube root of -3. Now that you have -3, all that it means is that \[-3=\sqrt[3]{-1}-2\]

OpenStudy (bloomlocke367):

so -3 is your y-value. The only thing you need to take the cube root of is the x-value that was given to you

OpenStudy (anonymous):

So the next one would be -2?

OpenStudy (bloomlocke367):

Yes! \(\Huge\color{lime}{\checkmark}\)

OpenStudy (anonymous):

Then 0, then 2?

OpenStudy (bloomlocke367):

Yep!

OpenStudy (anonymous):

Thank you so much!!

OpenStudy (bloomlocke367):

You're welcome! I'm glad I was able to help :)

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