Mathematics
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OpenStudy (anonymous):
What is (cos Θ − cos Θ)^2 + (cos Θ + cos Θ)^2?
sin^2 Θ
4cos^2 Θ
8
cos^2 Θ
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OpenStudy (astrophysics):
cos theta - cos theta = ?
OpenStudy (astrophysics):
it's like saying x - x, what does that give you?
OpenStudy (anonymous):
I know that part equals out to 0, but then I'm left with (cos theta + cos theta)^2
OpenStudy (anonymous):
I can't figure that out :(
OpenStudy (astrophysics):
Oh but in your case, there's a right answer yay!
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OpenStudy (anonymous):
It becomes \[\cos ^{2}\theta + \cos ^{2}\theta\]
zepdrix (zepdrix):
Expand? 0_o
But you said x-x = 0
why not apply that thinking to the other one?
x+x = 2x
OpenStudy (anonymous):
That's why I'm confused, it can't just equal 2x
zepdrix (zepdrix):
...?
zepdrix (zepdrix):
The other one is x+x
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OpenStudy (astrophysics):
the (cos theta+ cos theta)^2 term
OpenStudy (astrophysics):
cos theta + cos theta = 2cos theta, now square it
OpenStudy (anonymous):
Ohhh
OpenStudy (anonymous):
Well then it would be \[4\cos^2 \theta\]
OpenStudy (anonymous):
Well I'm an idiot
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OpenStudy (anonymous):
It was simple... -_-
OpenStudy (astrophysics):
Lol, don't worry for some reason I was thinking costheta+ sintheta
OpenStudy (astrophysics):
But in any case if you took long way or just added right away, you'd get same answer
OpenStudy (anonymous):
It's okay, thank you for helping though!
OpenStudy (astrophysics):
Yw :)