Question

@ganeshie8

Answer 1

8eihsenag@

Answer 2

send meeting id

Answer 3

oh ok. Let me open teamview

Answer 4

uhm... can not connect? O.o

Answer 5

is it the same ID you game me last time?

Answer 6

m14-003-342 ?

Answer 7

nope that was finished..
you need to start a fresh meeting..

click on Meeting, then you will see "presentation" icon on left pane

Answer 8

m09-542-741

Answer 9

what do I do now?

Answer 10

@ganeshie8 uhm... hello? :D

Answer 11

joining..

Answer 12

oh I see your name

Answer 13

It says you haven't started the presentation...

Answer 14

O.o how do I start it?

Answer 15

Let :
\[f(x) = \sum\limits_{k=0}^{n}a_kx^k\]
\[g(x) = \sum\limits_{k=0}^{n}a_k(x+jp)^k\]

show that \(f(x)\equiv g(x) \pmod{p}\)

Answer 16

\((x+jp)^k = x^k + p*(some integer)\)

Answer 17

let me skip typing the sum, so
it's x^i (jp)^(k-i), i from 0 to k ?

oh,

x^0 (jp)^(k-0) + x^1 (jp)^(k-1) + x^2 (jp)^(k-2) + ... + x^(k-1)(jp)^1 + x^k (jp)^0

yeah I see p as a factor of every term except the last term
p*(some integer) + x^k
yes

Answer 18

\((x+jp)^k = x^k + p*(some integer) \equiv x^k + 0 \pmod{p}\)