OpenStudy (kittiwitti1):

I DON'T GET IT How is either method wrong? - (the plus minus sign wasn't an option in their symbols bank?) http://prntscr.com/8ft0nc http://prntscr.com/8ft0se

2 years ago
OpenStudy (imqwerty):

\[\sqrt{4-(2\sin \theta)^2}\]\[\sqrt{4-4\sin^2\theta} \]\[\sqrt{4(1-\sin^2\theta)}\]and 1-sin^2(theta)=cos^2theta so we get \[\sqrt{4\cos^2\theta}\]=\[\pm2\cos \theta\]

2 years ago
OpenStudy (kittiwitti1):

I got that. The system isn't taking the answer in any form...

2 years ago
OpenStudy (imqwerty):

wait :D i didn see this - \[0<\theta <90\]

2 years ago
OpenStudy (kittiwitti1):

I tried these combinations\[\pm\sqrt{4\cos^{2}\theta}\]\[\sqrt{4\cos^{2}\theta},-\sqrt{4\cos^{2}\theta}\]yes? what does this mean?\[0\lt\theta\lt90?\]

2 years ago
OpenStudy (imqwerty):

that means that the angle theta lies between 0degrees and 90 deegrees

2 years ago
OpenStudy (kittiwitti1):

Yes ? I don't know what that applies to my answer lol, don't know how to

2 years ago
OpenStudy (imqwerty):

hav u tried this- \[2\cos \theta\]

2 years ago
OpenStudy (imqwerty):

tried that as the answer?

2 years ago
OpenStudy (kittiwitti1):

http://prntscr.com/8ft6av?

2 years ago
OpenStudy (imqwerty):

?

2 years ago
OpenStudy (kittiwitti1):

I have tried the positive version already. I have only one attempt left. However, I solved by hand and the answer I got was\[\pm2\cos\theta\]

2 years ago
OpenStudy (kittiwitti1):

I mean\[\pm2\left|\cos\theta\right|\]

2 years ago
OpenStudy (imqwerty):

yea

2 years ago
OpenStudy (kittiwitti1):

I don't get it. See, I got this one right without issues. http://prntscr.com/8ft75p

2 years ago
OpenStudy (kittiwitti1):

Maybe they are negative?

2 years ago
OpenStudy (kittiwitti1):

I can't risk the attempt though, got to make sure. :S

2 years ago
OpenStudy (imqwerty):

:) if they r not accepting positive then no scope for negative

2 years ago
OpenStudy (imqwerty):

maybe theres some error in their server

2 years ago
OpenStudy (kittiwitti1):

"No scope"?? -Confused- Yes maybe. One time I put space after a comma and they told me it was wrong. Someone on here said "take the space out" and I got it right after that... =_=

2 years ago
OpenStudy (imqwerty):

hahaha :D these things r annoying have u tried it like this- http://prntscr.com/8ft8mg i mean that space between theta nd that sec or tan or whateva

2 years ago
OpenStudy (kittiwitti1):

Sadly I tried it before, doesn't register as a trig function if I do that

2 years ago
OpenStudy (imqwerty):

have tried any such question before ...a question in which the answer was in the form of a trigo expression?

2 years ago
OpenStudy (kittiwitti1):

que?

2 years ago
hartnn (hartnn):

i would try \( 2| \cos \theta| \) for 1st and \(3\tan \theta \) for 2nd

2 years ago
hartnn (hartnn):

i mean \(3 |\tan \theta |\)

2 years ago
OpenStudy (kittiwitti1):

@hartnn first one does not accept second one I cannot try, I must be sure - only one submit attempt left ^^; sorry!

2 years ago
hartnn (hartnn):

its definitely not \(\pm\) the answer to a \(\sqrt{...}\) is always a positive

2 years ago
OpenStudy (imqwerty):

yes maybe it doesn't accept because of that bracket u put :P http://prntscr.com/8ftchw

2 years ago
OpenStudy (kittiwitti1):

The coding comes with the bracket. @imqwerty I cannot remove that. I have tried that.

2 years ago
OpenStudy (kittiwitti1):

@hartnn I was taught that there are two types of signs to a square root? I mean (-)(-)=+ right?

2 years ago
OpenStudy (imqwerty):

u must consult ur teacher

2 years ago
OpenStudy (kittiwitti1):

HAHAHAHHA my teacher is dumb she won't help me, I've tried. She sucks at technology and give us online homework LOL

2 years ago
hartnn (hartnn):

if already not tried, \(3 |\tan(\theta)|\) is worth trying for 2nd. don't forget to keep the fingers crossed :P

2 years ago
OpenStudy (kittiwitti1):

ehhh. I have done that?

2 years ago
OpenStudy (imqwerty):

lol

2 years ago
OpenStudy (imqwerty):

is this flvs? maybe u get the solution to this issue on google :)

2 years ago
hartnn (hartnn):

if x^2 = a then x = \(\pm \sqrt a\) thats because \((\sqrt a)^2 \\ and \\ (-\sqrt a)^2 \\ \text{both equal a}\)

2 years ago
hartnn (hartnn):

and \(\sqrt a\) is just one of them, and it can never be negative

2 years ago
OpenStudy (kittiwitti1):

????????

2 years ago
OpenStudy (kittiwitti1):

Ah my question key die from pressing too much LOL x_x!

2 years ago
hartnn (hartnn):

was just trying to explain why sqrt a can never be negative

2 years ago
OpenStudy (imqwerty):

so u got the 1st one wrong ....did it tell u the correct answer afterwards?

2 years ago
OpenStudy (kittiwitti1):

@imqwerty No, it does not tell me the answer. :[ @hartnn I am still lost, what o-o

2 years ago
OpenStudy (kittiwitti1):

...My computer is very laggy right now

2 years ago
OpenStudy (imqwerty):

:)

2 years ago
hartnn (hartnn):

go for \(3|\tan \theta |\) !

2 years ago
OpenStudy (kittiwitti1):

...Fine, I blame you guys if I fail the question lol

2 years ago
OpenStudy (kittiwitti1):

http://prntscr.com/8ftleb ... @hartnn it's wrong.

2 years ago
OpenStudy (kittiwitti1):

I don't get iiiit! D:

2 years ago
hartnn (hartnn):

the system should atleast take equivalent answers.. seems to be a faulty system, and an incorrect way to test students! maybe it would have accepted \(|3 \tan \theta |\)

2 years ago
OpenStudy (kittiwitti1):

The teacher said the answer must be a|cos theta| format

2 years ago
hartnn (hartnn):

it needs to have cos in ti ??

2 years ago
OpenStudy (kittiwitti1):

no that is an example trig function

2 years ago
hartnn (hartnn):

sec^2 x = 1/cos^2 x

2 years ago
OpenStudy (kittiwitti1):

LOL

2 years ago
hartnn (hartnn):

3 | tan \(\theta \)| is indeed in that format

2 years ago
OpenStudy (kittiwitti1):

Yeah idk why they say it's wrong. This question have the right format http://prntscr.com/8ftnwx

2 years ago
OpenStudy (kittiwitti1):

@hartnn \[\sin10=\cos{?}\]

2 years ago
OpenStudy (kittiwitti1):

10 degree

2 years ago
OpenStudy (kittiwitti1):

Wait never mind

2 years ago
OpenStudy (kittiwitti1):

I got it

2 years ago
hartnn (hartnn):

sin x = cos(90-x) here x = 10 whats 90 -10 ?

2 years ago
hartnn (hartnn):

ok

2 years ago
OpenStudy (kittiwitti1):

lolol sorry

2 years ago
hartnn (hartnn):

no problem :)

2 years ago
OpenStudy (kittiwitti1):

But I don't get the formatting of those problem, confusing D:

2 years ago
OpenStudy (kittiwitti1):

Also: "Use Definition II to explain why it is possible to find an angle θ that will make tan θ as large as we wish" (what?!)

2 years ago
OpenStudy (kittiwitti1):

@hartnn ? ?

2 years ago
hartnn (hartnn):

whats the Def II? they are asking why tan 90n goes to infinity or -infinity

2 years ago
OpenStudy (kittiwitti1):

Yes. And I got wrong answer here too LOL very sorry (8 cos 30°)2 I put 96 is wrong

2 years ago
OpenStudy (kittiwitti1):

^2 sorry not x2

2 years ago
hartnn (hartnn):

cos 30 = sqrt 3/2 8 cos 30 = 4 sqrt 3 its square 16*3 = ...

2 years ago
OpenStudy (kittiwitti1):

:o Oh um um um

2 years ago
OpenStudy (kittiwitti1):

UM.... 48?!

2 years ago
hartnn (hartnn):

yes

2 years ago
OpenStudy (kittiwitti1):

lol! I got it :D

2 years ago
OpenStudy (kittiwitti1):

Thank you ! :]

2 years ago
hartnn (hartnn):

welcome ^_^

2 years ago
OpenStudy (kittiwitti1):

But... what about the weird question? Do I just skip it for now? o-o

2 years ago
hartnn (hartnn):

take 2nd opinion... maybe ask some other expert or you can skip it, if you're not in any hury

2 years ago
OpenStudy (kittiwitti1):

Okay.

2 years ago
OpenStudy (kittiwitti1):

@hartnn Sorry question: http://prntscr.com/8ftxg2 ?

2 years ago
hartnn (hartnn):

cos 30 = sqrt 3/2 cos^2 30 = 3/4 4cos^2 30 = 3

2 years ago
hartnn (hartnn):

6 sin 30 = 6/2 =3

2 years ago
hartnn (hartnn):

finally, 3+3 =6

2 years ago
OpenStudy (kittiwitti1):

o_o Oh.

2 years ago
OpenStudy (kittiwitti1):

So I should not do it the quadratic formula way yes?

2 years ago
OpenStudy (kittiwitti1):

Too complex? lol

2 years ago
hartnn (hartnn):

you can, but that not required, because we know the values already

2 years ago
OpenStudy (kittiwitti1):

ah ok. got it

2 years ago
OpenStudy (kittiwitti1):

−5 sin 2x if x = 30, how much? I don't know how to do a sin b x

2 years ago
hartnn (hartnn):

x = 30, so 2x = 60 sin 60 = sqrt 3/2 so -5 sqrt 3/2

2 years ago
OpenStudy (kittiwitti1):

OOOOOOH okay! Thank you :)

2 years ago
OpenStudy (kittiwitti1):

Umm last one, this really confusing me http://prntscr.com/8fu4ew?

2 years ago
OpenStudy (kittiwitti1):

?

2 years ago
OpenStudy (kittiwitti1):

@hartnn

2 years ago
hartnn (hartnn):

tan is opposite/adjacent so it has to be the 1st one only

2 years ago
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