An acid with a Ka of 2x10^-6 is used to make a buffer. what is the approximate pH of the solution if the buffer has equal concentrations of both the acid and its conjugate base?

Question

photon336 · Answer

Between 
4-5
2-3
3-4
5-6

photon336 · Answer

@Rushwr @Woodward

photon336 · Answer

$$Ka = \frac{ [H ^{+}][A ^{-}]  }{ [HA] }$$

photon336 · Answer

pH = pKa + log [A-/HA]

I guess if the concentration of acid HA equals the conjugate base A-

Log[1] = 0

So the pH would be equal to the pKa and I guess this would be where the greatest buffering capacity would be.

PH = pKa

anonymous · Answer

Yeah, definitely that's what I was thinking that looks right to me.