A man takes a photo of a bridge on holiday. The arch of
the bridge in her photograph can be modelled by the equation
y = −0.11x
2 + 1.26x + 1.20,
where x is the horizontal distance of the inner edge of the bridge from
the centre line of the photo, and y is the vertical distance from the
bottom of the photo (both measured in cm).
(i) Find the y-intercept of the parabola y = −0.11x^2 + 1.26x + 1.20.
(ii) (1) Find the coordinates of the point where the line x = 9 meets
the parabola.

Question

A man takes a photo of a bridge on holiday. The arch of
the bridge in her photograph can be modelled by the equation
y = −0.11x
2 + 1.26x + 1.20,
where x is the horizontal distance of the inner edge of the bridge from
the centre line of the photo, and y is the vertical distance from the
bottom of the photo (both measured in cm).
(i) Find the y-intercept of the parabola y = −0.11x^2 + 1.26x + 1.20. 
(ii) (1) Find the coordinates of the point where the line x = 9 meets
the parabola.

nnesha · Answer

y-intercept is a point when line line intersect y-axis 
when x =0 
so to find y-intercept substitute x for 0

nnesha · Answer

y= -.11x isn't a parabola

nnesha · Answer

oh nvm  y = −0.11x^2 + 1.26x + 1.20.  this is your equation so replace all x's with 0

nnesha · Answer

question ???? understood? or not ? ???

anonymous · Answer

yea h so y =1.2

anonymous · Answer

what i dont get is the second part