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Please help!! Medal!! Find the 500th term of the sequence below. 24,30,36,42,48,.... a.3018 b.3024 c.3042 d.2994
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the first term is 24.the next term is 24+6. so common difference is 6. then use this formula to find the 500th term.\[a_{n}=a _{1}+(n-1)d\]
an=a1 +(n-1) 6
B
an=24+499*6
How did u get 499?? @amirreza1870
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your n is 500 so n-1 is 499.
Does it always to be subtract 1? @amirreza1870
ye.s if you want to find 150th (n) term of your arithmetic sequence you should multiply common difference by 149 (n-1) and add the value of this multiplication to the first term. an=a1+(n-1)d
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