Please help!! Medal!!
Find the 500th term of the sequence below.
24,30,36,42,48,....
a.3018
b.3024
c.3042
d.2994

Question

Please help!! Medal!!
Find the 500th term of the sequence below.
24,30,36,42,48,....
a.3018
b.3024
c.3042
d.2994

anonymous · Answer

the first term is 24.the next term is 24+6. so common difference is 6.
then use this formula to find the 500th term.$$a_{n}=a _{1}+(n-1)d$$

clamin · Answer

an=a1 +(n-1) 6

clamin · Answer

B

anonymous · Answer

an=24+499*6

clamin · Answer

How did u get 499?? @amirreza1870

anonymous · Answer

your n is 500 so n-1 is 499.

clamin · Answer

Does it always to be subtract 1? @amirreza1870

anonymous · Answer

ye.s if you want to find 150th (n) term of your arithmetic sequence you should multiply  common difference by 149 (n-1) and add the value of this multiplication to the first term.
an=a1+(n-1)d