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Mathematics 11 Online
OpenStudy (anonymous):

Write an equation. The half-life of Rhodium, Rh-106 is about 30 seconds, you start with 500 grams

OpenStudy (anonymous):

Please can someone help? I just got out of the hospital and this is homework that I missed.

OpenStudy (anonymous):

I just can't figure out the equation on the new meds I'm on:(

OpenStudy (owlcoffee):

First of all, we'd have to figure out how much Rhodium we lose every second.

OpenStudy (anonymous):

we lose 50% rhodium every second which means that it is not linear

OpenStudy (owlcoffee):

What is 500 divided 30?

OpenStudy (anonymous):

it wouldn't be 500/30. it would be 500/2 and then 250/2 and then 125/2 and so on

OpenStudy (anonymous):

wouldn't it?

OpenStudy (anonymous):

I just need to answer it in y=m(x)+b format

OpenStudy (owlcoffee):

No, if you want to determine, on average, the amount of RH lost in 30 secs, you'd have to first find how much you lose each second. For that matter, you divide the total mass with the total amount of time.

OpenStudy (anonymous):

why would I need the average? I need to graph it so it is non linear curve. Ive already graphed it just need to get the equation for it.

OpenStudy (anonymous):

why aren't you answering?

OpenStudy (owlcoffee):

Because we need to establish a proportion that will allow us to create the "slope" of the line that will compose that graph you wrote.

OpenStudy (anonymous):

ok, well 500/30 is 16.666

OpenStudy (owlcoffee):

Good. So, if we were to write a function, we would write that multiplied "x" that represents the amount of second that has passed: \[f(x)=500-(16.666)x\] if we call "f(x)" as "y", we will obtain: \[y=500-(16.666)x\]

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