Question

Write the partial fraction decomposition of the rational expression.

Answer 1

http://assets.openstudy.com/updates/attachments/5224e4dbe4b0750826e245ae-gponce28-1378149870417-f1q1g1.jpg

Answer 2

@Nnesha

Answer 3

know how to start??

\(\large \dfrac{A}{x}+\dfrac{B}{x-2}+\dfrac{C}{x-4}\)

Answer 4

what is that

Answer 5

partial fraction decomposition of your expression.

once you find A,B,C
you're done

Answer 6

\(\large \dfrac{18x^2 -68x+24}{x(x-2)(x-4)} = \dfrac{A}{x}+\dfrac{B}{x-2}+\dfrac{C}{x-4}\)

Answer 7

now simplify the right side, so that it has one common denominator

Answer 8

like

1/a + 1/b = (b+a)/ab

Answer 9

let me give you a start

denominator = x(x-2)(x-4)

numerator = A (x-2)(x-4) + B.................

Answer 10

im so cunfused

Answer 11

have you solved a similar problem before?

Answer 12

no i just srted this class

Answer 13

too early to take that example then

Answer 14

start with something easier
\(\dfrac{2x+3}{(x+1)(x+2)} \)

Answer 15

ooh;

Answer 16

to decompose that into partial fractions means, we need to have fractions with linear denominators

\(\dfrac{2x+3}{(x+1)(x+2)} = \dfrac{A}{(x+1)}+\dfrac{B}{(x+2)}\)

Answer 17

then find A,B with any method that you prefer.

I tried to discuss One of the method earlier

Answer 18

taking a common denominator on right side

\(\dfrac{A}{(x+1)}+\dfrac{B}{(x+2)} = \dfrac{A(x+1)+B(x+2)}{(x+1)(x+2)}\)

makes sense?