Question

WILL GIVE MEDAL! What is the value of 2x^-2 y^-2 for x=3 and y=-2

Answer 1

\[2x ^{-2}y ^{-2}\] this what u have said right? Just substitute the values and see

Answer 2

yes. but i need help

Answer 3

which part do u need help

Answer 4

figuring the whole thing out

Answer 5

okai,
\[2x ^{-2}y ^{-2} = 2 * 3^{-2} * -2^{-2}\] right?

Answer 6

i guess idk thats why i need help

Answer 7

in tha step I have substituted the values of x and y which we are given with ! Did u get that part ?

Answer 8

yes.

Answer 9

When u have a negative exponent like \[x ^{-n}\] You can also write it as \[\frac{ 1 }{ x ^{n} }\] okai ?

Answer 10

ok

Answer 11

ok so what now?

Answer 12

I got a little wrong there y also has a negative exponent so we can take that down too !
so it will be \[\frac{ 2 }{ 3^{2} * -2^{2} }\]

Answer 13

ok lol i was like why did you dlete it. but anyways i got it. whats next

Answer 14

now just simplyfy
when u multiply 2 negatives it becomes positive right?
we knwo -2 ^2 means -2 x -2 right? so that makes it 4!

Answer 15

so 2/2?

Answer 16

we know 3^2 = 9
\[\frac{ 2 }{ 9 * 4 }\]

Answer 17

did u get it ?

Answer 18

so 2/36

Answer 19

but there is no answer like that on here

Answer 20

ohhh 1/18?

Answer 21

there is that one