Get rid of the fraction by multiplying by the common denominator
(x-2)/18 = (x-3)/15
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OpenStudy (anonymous):
270
OpenStudy (anonymous):
15x-30+18x-54 on top? @mathway
OpenStudy (anonymous):
but i have a common denominator of three
OpenStudy (anonymous):
Are you finding for x?
OpenStudy (anonymous):
it just says get rid of the fractions by finding the common denominator on the paper
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OpenStudy (anonymous):
The common denominator is 3.
OpenStudy (anonymous):
Yeah, after I find the common denominator then what do I do to the top? Does it change?
OpenStudy (anonymous):
@mathway
OpenStudy (anonymous):
No
OpenStudy (anonymous):
270 is actually the common deoninator
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OpenStudy (anonymous):
ugghhh i'm confused
OpenStudy (anonymous):
270 works because it's 18*15. Any number that both 18 and 15 go into works. I think 90 is the smallest.
I think this is what you're trying to do\[\frac{ 270(x-2) }{ 18 }=\frac{ 270(x-3) }{ 15 }\]
and then reduce the whole numbers
\[15(x-2)=18(x-3)\]
Which is exactly what you got when you cross multiplied
OpenStudy (anonymous):
see you made me confused a while ago >.< thanks @peachpi !