Question

Find the point (0, b) on the y-axis that is equidistant from the points (4, 4) and (4, -3).

Answer 1

so you have an equation
you want the distance from (0,b) to (4,4) to be the same as the distance from (0,b) to (4,-3)

Answer 2

use distance formula twice
once for both sets of points
then equate and solve for b

Answer 3

well I got -1/14, but its saying its wrong

Answer 4

so can I ask what equation you solved?
did you solve the one I asked you to?

Answer 5

yes I used two distance formula for (0,b)(4,4) and (0,b)(4,-3) and i got 24-8b+b^2=25+6b+b^2 which i got 1/14

Answer 6

\[\sqrt{(0-4)^2+(b-4)^2}=\sqrt{(0-4)^2+(b-(-3))^2} \\ \\ \text{ square both sides } \\ (0-4)^2+(b-4)^2=(0-4)^2+(b-(-3))^2\]
now 0-4 is -4
and (-4)^2 =16
also b-(-3) is the same as b+3
so you have:
\[16+(b-4)^2=16+(b+3)^2 \\ \text{ subtract 16 on both sides } (b-4)^2=(b+3)^2\]
is this what you try to solve ?

Answer 7

this means you either have b-4=b+3 or b-4=-(b+3)
see which one of these equations gives you a solution

Answer 8

I'm gonna check on my croissant dough unless you have a question

Answer 9

im just trying it out to see, i think ill be fine

Answer 10

ok well I will be back in a few if not

Answer 11

ah i got it, thank you so much

Answer 12

awesome