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OpenStudy (anonymous):
OpenStudy (anonymous):
same method as the last one
distribute first
OpenStudy (anonymous):
@satellite73 ohh okay thanks
OpenStudy (anonymous):
i can check your answer if you like
OpenStudy (anonymous):
Okay sounds good, Give me a minute
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OpenStudy (anonymous):
I got 2x+y=2
OpenStudy (anonymous):
lets go slow
OpenStudy (anonymous):
what do you get when you remove the partentheses using the distributive law for
\[2(x-3)\]?
OpenStudy (anonymous):
2x-6
OpenStudy (anonymous):
ok good
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OpenStudy (anonymous):
so now we are at
\[y+4=2x-6\]
OpenStudy (anonymous):
Do we move all the variables to one side?
OpenStudy (anonymous):
yes and no
OpenStudy (anonymous):
we don't "move" in math, just add, subtract, multiply, divide
OpenStudy (anonymous):
you want the variables on the left or the right?
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OpenStudy (anonymous):
left
OpenStudy (anonymous):
ok so don't "move" the \(2x\) to the left, "subtract" \(2x\) from both sides
OpenStudy (anonymous):
yes, got that. so 2x-y+4=6
OpenStudy (anonymous):
then we subtract -4 to both sides? right?
OpenStudy (anonymous):
the minus sign goes in front of the \(2x\) not behind it
\[-2x+y+4=-6\]
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OpenStudy (anonymous):
Ohh okay! I see now.
OpenStudy (anonymous):
now you would subtract the \(4x\) from both sides
also don't drop the minus sign in front of the \(-6\) on the right
OpenStudy (anonymous):
oops i mean subtract \(4\) from both sides, sorry b
OpenStudy (anonymous):
Right no worries so, -2x+y=-10
OpenStudy (anonymous):
right
maybe one more step, maybe not
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OpenStudy (anonymous):
some people like the coefficient of the x term to be positive
if so, just change the sign of everything, go form
\[-2x+y=-10\] to
\[2x-y=10\] same equation