Algebra
23 Online
OpenStudy (anonymous):
Okay now I have no clue how to solve this one.
Rewrite the equation in Ax+By=C form.
Use integers for A,B,C
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OpenStudy (anonymous):
OpenStudy (anonymous):
arh...
OpenStudy (anonymous):
no biggie
clear the fraction by multiplying EVERYTHING by 2
OpenStudy (anonymous):
Right, So how exactly? Do you make 1/2 to just 2?
OpenStudy (anonymous):
@satellite73
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OpenStudy (anonymous):
no dear \(2\times (-\frac{1}{2})=-1\)
OpenStudy (anonymous):
but don't forget to multiply all by 2
all the way across
left hand side and right hand side,each term
OpenStudy (anonymous):
Oh. okay let me try to solve it :)
OpenStudy (anonymous):
kk
OpenStudy (anonymous):
|dw:1442282234913:dw|
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OpenStudy (anonymous):
Right?
OpenStudy (anonymous):
yesh...
OpenStudy (anonymous):
wait im completely confused
OpenStudy (anonymous):
lets go slow again
you want to get rid of the fraction right? so that the coefficients are "integers"
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
you got
\[y=-\frac{1}{2}x-3\]
OpenStudy (anonymous):
to get rid of the two in the denominator, multiply both sides by \(2\)
\[2\times y=2\times (-\frac{1}{2}x-3)\]
OpenStudy (anonymous):
distribute on the right hand side
OpenStudy (anonymous):
2y=-1x-3
OpenStudy (anonymous):
hmm looks like you forgot the distributive property
you also have to multiply \(-3\) by \(2\)
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OpenStudy (anonymous):
ohh so 2y=-1x-6
OpenStudy (anonymous):
correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
now add \(x\) to both sides and you are done
OpenStudy (anonymous):
1x+2y=6
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OpenStudy (anonymous):
yeah but drop the \(1\) or your teacher will think you are daft
OpenStudy (anonymous):
so just x+2y=6
OpenStudy (anonymous):
damn, dropped the minus sign again on the right didn't you?
OpenStudy (anonymous):
x-2y=6???
OpenStudy (anonymous):
a common mistake actually
now on the right, it was \(-6\) so it is still \(-6\)