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Mathematics 10 Online
OpenStudy (sloppycanada):

How do I solve piecewise functions? I cannot tell you how many times I have stared at my notes and done the practice. https://gyazo.com/8740807019fb8b146a7ec27a3565554e

myininaya (myininaya):

f(-2) can be evaluated by the piece that includes x=-2

myininaya (myininaya):

is -2 in the set of numbers that is described by x>=0? by x<-3? or by -3<=x<0?

OpenStudy (sloppycanada):

Yes? the last one?

myininaya (myininaya):

yes the last one -2 is between -3 and 0

myininaya (myininaya):

so you use f(x)=2 since x is between -3 and 0

myininaya (myininaya):

which means f(anything in that interval)=2

myininaya (myininaya):

f(-1)=2 f(-1/2)=2 f(-2.534)=2

OpenStudy (sloppycanada):

so that means my answer is 2? So okay, the way I see is if the f(-2) or whatever number it is, happens to be in the set of functions, then the answer to f(x) is the opposite?

myininaya (myininaya):

what?

myininaya (myininaya):

I used f(x)=2 since x is between -3 and 0

myininaya (myininaya):

if it said evaluate f(-5) I would have used f(x)=|x+3| since x is less than -3

myininaya (myininaya):

f(-5)=|-5+3|=|-2|=2

OpenStudy (sloppycanada):

so it has to fit in the thing? i'm confused now.

myininaya (myininaya):

remember the first thing we looked at is what set of x values our x was included in then we used the corresponding piece

myininaya (myininaya):

another example if we wanted to evaluated f(-10) -10 is less than -3 and our function says use f(x)=|x+3| if x is less than -3 so f(-10)=|-10+3|=-7|=7

myininaya (myininaya):

another example if we wanted to evaluate f(20) well 20 is greater than 0 and our function says to use f(x)=x if x greater than or equal to 0 so f(20)=20

OpenStudy (sloppycanada):

You lost me.

myininaya (myininaya):

oh which part?

myininaya (myininaya):

f(-10) or f(20) or what?

OpenStudy (sloppycanada):

which means f(anything in that interval)=2

OpenStudy (sloppycanada):

Like I said, I really don't get these piecewise functions..

myininaya (myininaya):

before I said that I said this "so you use f(x)=2 since x is between -3 and 0" the interval being [-3,0) actually since it says to include -3 f(anything in that interval)=2 means any x value in [-3,0) will give us the output 2 when put into our function examples f(-3)=2 f(-2.9999)=2 f(-2.5)=2 f(-2)=2 f(-1.99)=2 f(-1.5)=2 f(-1/2)=2 f(-1/5)=2

OpenStudy (sloppycanada):

but how did you get 2 from -2?

myininaya (myininaya):

Your function says to use f(x)=2 if -3<=x<0

myininaya (myininaya):

and -2 certainly falls in that interval

myininaya (myininaya):

f(-2)=2 since -3<=-2<0

OpenStudy (sloppycanada):

Okay, so that little comma thing is like "if this answer is right, use "2" for x "

myininaya (myininaya):

no x is -2 in your problem f(x) or y is 2 for your problem

myininaya (myininaya):

if it did say evaluate f(2) then you would look at the inequalities (or intervals whatever you want to call them) and see which one it satisfies 2>=0 so we use f(x)=x since x>=0 for this example so f(2)=2

myininaya (myininaya):

does this still make no sense?

myininaya (myininaya):

your function says: if x>=0 then use f(x)=x if x<-3 then use f(x)=|x+3| if -3<=x<0 then use f(x)=2

myininaya (myininaya):

find which if part is true for your x then use function that corresponds to that inequality

myininaya (myininaya):

to find the output for the function

OpenStudy (sloppycanada):

x = -2 and y = 2

OpenStudy (sloppycanada):

then what do I do with all these commas?

myininaya (myininaya):

You don't need to do anything with them

myininaya (myininaya):

if you want you can replace them with the word if if you prefer that

myininaya (myininaya):

but you already found f(-2)

OpenStudy (sloppycanada):

okay, then what do I do with it?

myininaya (myininaya):

what does it refer to?

myininaya (myininaya):

what third bit?

myininaya (myininaya):

I'm absolutely lost on what we are talking about now

myininaya (myininaya):

is there another question or something?

myininaya (myininaya):

The only question I see is find f(-2) and we done that I don't see a third or even a second question on the picture you posted

OpenStudy (sloppycanada):

but what did we find? I'm confused on what we actually found.

myininaya (myininaya):

we found f(-2)

OpenStudy (sloppycanada):

and what is f(-2)? 2?

myininaya (myininaya):

yes f(-2)=2

myininaya (myininaya):

remember if we have -3<=x<0 then we use f(x)=2 and we had x=-2 was included in -3<=x<0 so we used f(x)=2 to find f(-2)

myininaya (myininaya):

insert any number from the inequality -3<=x<0 into f(x) and you get the output 2 insert any number from the inequality x>=0 into f(x) you get the output x insert any number from the inequality x<-3 into f(x) you get the output |x+3|

OpenStudy (sloppycanada):

so my answer to this problem is 2, which I think is C?

myininaya (myininaya):

So I guess you are asking me this question for the 4th time because you still don't understand why f(-2)=2?

OpenStudy (sloppycanada):

pretty much.

myininaya (myininaya):

Ok do you understand the below? \[f(x)=x \text{ if } x \ge 0 \\ f(x)=|x+3| \text{ if } x<-3 \\ f(x)=2 \text{ if } -3 \le x <0 \]

myininaya (myininaya):

we plugged in -2 we are looking for f(-2) we replaced x with -2 replace all the x's with -2 \[f(-2)=-2 \text{ if } -2 \ge 0 \\ f(-2)=|-2+3| \text{ if } -2<-3 \\ f(-2)=2 \text{ if } -3 \le x <0\] the only line that is true here is the last line do you see why?

myininaya (myininaya):

*\[f(-2)=-2 \text{ if } -2 \ge 0 \\ f(-2)=|-2+3| \text{ if } -2<-3 \\ f(-2)=2 \text{ if } -3 \le -2 <0\]*

myininaya (myininaya):

the only line that is true here is the last line do you see why?

myininaya (myininaya):

the last line is the only line that is true since: \[f(-2)=-2 \text{ if } -2 \cancel{\ge} 0 \\ f(-2)=|-2+3| \text{ if } -2\cancel{<}-3 \\ f(-2)=2 \text{ if } -3 \le -2 <0\]

OpenStudy (sloppycanada):

yes, i get why we have 2. kinda. but i'm not sure what to do with it. Is it the answer to the problem?

myininaya (myininaya):

the last line says f(-2)=2 ...

OpenStudy (sloppycanada):

which makes 2 our answer. so the answer to the original problem is 2.

myininaya (myininaya):

did you want to try more examples? if so see if you can find f(-100)

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